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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque d1(t, t+10); sort(d1.begin(), d1.end()); deque::iterator it = upper_bound(d1.begin(), d1.end(), B(4), greater()); for_each(it, d1.end(), Out(cout)); cout< return 0; } Program outputs:
Suggested Answer: C
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27 comments · newest first
LE
Leatha
9 months ago
I can't believe it sorts and outputs like that!
AH
Ahmed
9 months ago
Definitely not a compilation error, it runs smoothly.
BE
Bettyann
9 months ago
Wait, is there a compilation error?
BR
Brittni
9 months ago
I think it outputs 5 6 7 8 9 10.
LY
Lynsey
10 months ago
Looks like it should compile fine.
AL
Aleisha
11 months ago
I feel like there might be a compilation error because of how the deque is initialized with the array. Wasn't there something tricky about that?
LA
Latanya
11 months ago
I practiced a similar question, and I think the output should be the values greater than 4, but I can't recall if it includes 4 itself.
CY
Cyril
11 months ago
I'm not entirely sure, but I remember something about `upper_bound` needing a sorted range. Does the sort function work as expected here?
KI
Kizzy
11 months ago
I think the code should compile fine since it uses standard libraries and the class is defined correctly.
KE
Kenny
12 months ago
Ah, I see now. The `greater()` predicate is used to reverse the sorting order, so the `upper_bound` call finds the first element less than or equal to 4. That means the output should be the elements from 4 to 10, which is option B.
MA
Maryrose
12 months ago
I'm not entirely sure about this one. The use of the `greater()` predicate is throwing me off, and I'm not confident I fully understand how the `upper_bound` function works in this context. I'll need to review the C++ standard library documentation to be sure.
HI
Hildred
12 months ago
Okay, I think I've got it. The `deque` is initialized with the array `t`, then sorted in ascending order. The `upper_bound` call finds the first element greater than 4, and the `for_each` loop prints those elements. The answer should be B.
CA
Carissa
1 year ago
Hmm, I'm a bit confused by the `greater()` predicate used in the `upper_bound` call. I'll need to think through how that affects the sorting and search behavior.
ET
Ettie
1 year ago
This looks like a tricky C++ question involving the use of the `deque` container and the `upper_bound` algorithm. I'll need to carefully read through the code and understand the logic to determine the correct output.
GE
Georgene
1 year ago
Hmm, I'm not sure about this one. Let me double-check the logic. Oh, I got it! D is the correct answer. Nice try, tricky question!
FL
Flo
1 year ago
Ha! I bet the compiler will just laugh at this code and throw a tantrum. C is the way to go here.
GR
Graciela
10 months ago
Definitely a compilation error. No way it runs!
ME
Melita
10 months ago
I think you're right! That code looks messy.
VE
Vesta
10 months ago
C is the best choice here. Good call!
AS
Ashanti
11 months ago
I wouldn't be surprised if it just crashes.
DO
Dominic
1 year ago
No way, the output has to be B! The code sorts the deque in ascending order, so the output should be the sorted elements.
NI
Nieves
1 year ago
I think the correct answer is D. The code sorts the deque in ascending order and then uses upper_bound to find the iterator pointing to the first element greater than 4. It then prints the remaining elements in descending order.
RE
Reena
1 year ago
No, it actually prints the elements in ascending order after sorting.
TR
Tracey
1 year ago
I think the correct answer is D.
IV
Ivory
1 year ago
I'm not sure, but I think it might be C) compilation error.
AH
Ahmed
1 year ago
I agree with Amalia, the code sorts the deque in ascending order.
AM
Amalia
1 year ago
I think the answer is B) 1 2 3 4 5 6 7 8 9 10.