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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list
int t2[] ={ 3, 2, 6, 9, 0 };
deque
l1.sort();
d1.sort();
l1.merge(d1);
print(l1.begin(), l1.end());
print(d1.begin(), d2.end()); cout< return 0; }
Suggested Answer: D
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7 comments · newest first
TE
Terrilyn
11 months ago
Just a heads up, the output won't include d1 at all.
LA
Laurena
12 months ago
Yeah, the merge function needs iterators from the same container type.
JU
Julio
12 months ago
Wait, are you serious? I thought it would just output the merged list.
TE
Teri
12 months ago
Totally agree, the d2 variable is not defined!
KR
Krissy
1 year ago
The program will actually have a compilation error.
AR
Arlette
1 year ago
I've worked with HPE OneView before, so I'm familiar with the Remote Support feature. Based on my experience, I believe the correct answer is option B, which covers any Gen8, Gen9, and Gen10 servers managed using HPE OneView. I'll double-check my understanding, but I'm feeling good about this one.
JO
Johnathon
1 year ago
Okay, I think it's either option A or C that looks right. I'll eliminate the other options and then decide between those two.