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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
list
set
if (s1.count(3) == 2) {
s1.erase(3);
}
for(set
cout<<*i<<" ";
}
return 0;
}
Suggested Answer: A
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7 comments · newest first
GE
Gerald
11 months ago
No compilation errors here!
AR
Arleen
12 months ago
I thought it would show duplicates!
EL
Ellsworth
12 months ago
Wait, how can count(3) be 2?
CH
Christiane
12 months ago
Definitely outputs 1 2 4 5!
MA
Mabel
1 year ago
The set will only keep unique values.
KI
King
1 year ago
I'm feeling pretty confident about this one. The requirement to run the new version alongside the old version before switching over points directly to a blue/green deployment strategy. Let's go with that.
AN
Anabel
1 year ago
Hmm, this looks like a tricky one. I'll need to carefully read through the error message and the options to figure out the best approach.