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What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t[]={3,2,4,1,5,10,9,7,8,6}; vector v1(t,t+10); sort(v1.begin(), v1.end(), greater()); cout<<*min_element(v1.begin(), v1.end()); return 0; } Program outputs:
Suggested Answer: E
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15 comments · newest first
BR
Brandon
18 days ago
Right, so B) 1 makes sense.
DI
Dierdre
23 days ago
Exactly, so the min_element will still find the smallest.
MA
Marg
28 days ago
But it sorts in descending order first.
BR
Brandon
1 month ago
The output should be 1, since it's the smallest after sorting.
DI
Dierdre
1 month ago
I feel like there's a compilation error.
MA
Marg
1 month ago
I think it will compile fine.
YO
Yolando
2 months ago
I disagree, it should output 3 based on the sorting logic.
RO
Rosio
2 months ago
Definitely not a compilation error, that's for sure!
SH
Shenika
2 months ago
Wait, does it really sort in descending order?
AL
Alfreda
2 months ago
I think it outputs 1, since that's the smallest value.
FE
Felix
2 months ago
The code compiles fine, no errors.
MA
Martina
2 months ago
I have a feeling there might be a compilation error because of how the array of `B` objects is initialized.
LI
Lino
3 months ago
This reminds me of a practice question where we had to sort a vector of objects. I feel like the output should be the smallest value after sorting.
AL
Alise
3 months ago
I'm not entirely sure, but I remember something about how `min_element` works with custom types. It might not return what we expect.
VI
Vicki
3 months ago
I think the code should compile fine since all the necessary operators and constructors are defined.