What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
int t[]={1,2,3,4,5};
std::vector
std::vector
v1.resize(10);
v2.reserve(10);
std::vector
while (i != v1.end()) { std::cout<
i = v2.begin();ii=0;
while (i != v2.end()) { std::cout<
return 0;
}
Suggested Answer: E
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36 comments · newest first
AL
Altha
11 months ago
I agree, D seems like the most likely output here.
ME
Merilyn
11 months ago
Wait, why would it output so many 1s? That seems off.
TE
Tenesha
11 months ago
Definitely not a compilation error.
AL
Altha
11 months ago
I think the output will be a mix of 1s and 0s.
CU
Curtis
11 months ago
Looks like it should compile fine.
LA
Lachelle
12 months ago
I feel like the program will just print a bunch of ones because of how the iterator is being used, but I could be wrong.
RI
Ria
12 months ago
The output might be a mix of the original array and zeros, but I can't recall exactly how the resizing affects the output.
BR
Brett
12 months ago
I remember something similar where using an uninitialized index caused issues. I wonder if that's what's happening here with "ii??".
EL
Elvis
1 year ago
I think the code should compile fine since it uses standard vector operations, but I'm not sure about the iterator part.
VI
Vivan
1 year ago
I've seen similar questions before, so I think I have a good handle on this. Let me walk through the code and the expected behavior of the vector operations.
JA
Jarod
1 year ago
I'm not sure about this one. The output doesn't seem straightforward, and I'll need to think it through carefully to determine the correct answer.
SA
Salena
1 year ago
Okay, I think I've got this. The key is understanding the difference between the capacity and size of the vectors. Let me work through it step-by-step.
LI
Lisbeth
1 year ago
Hmm, I'm a bit confused about the use of `reserve()` and `resize()` here. I'll need to review how those methods work to figure out the expected output.
AR
Ardella
1 year ago
This looks like a tricky one. I'll need to carefully step through the code to understand what's happening with the vectors.
JO
Jose
1 year ago
Wait, is that a typo in the loop? I think the '??' is supposed to be '++'. Gotta pay attention to the small details!
AR
Artie
1 year ago
B) compilation error
RO
Rosann
1 year ago
B) compilation error
TA
Tamesha
1 year ago
B) compilation error
AL
Alecia
1 year ago
I'm picturing the output being a weird mix of 1s and the original elements. This should be a fun one to work through.
CH
Christoper
1 year ago
C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
CH
Christoper
1 year ago
B) compilation error
CH
Christoper
1 year ago
A) program outputs 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
NI
Nichelle
1 year ago
Haha, I can already see the compiler throwing a fit at this code. Time to brush up on my C++ vector knowledge!
RO
Rosio
1 year ago
I believe the program will output 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5.
RO
Rosio
1 year ago
Yeah, the code looks like it might have some issues with iterators.
RO
Rosio
1 year ago
I think it will output a compilation error.
TR
Trina
2 years ago
Ah, the classic vector resizing and copying conundrum. I bet the answer has something to do with the difference between resize() and reserve().
RO
Roosevelt
1 year ago
B) compilation error
RO
Roosevelt
1 year ago
C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
MI
Micaela
2 years ago
This looks like a tricky one! I'm going to have to think through the memory management implications carefully.
HO
Howard
1 year ago
I think it will result in a compilation error
HO
Howard
1 year ago
No, it will output 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5
HO
Howard
1 year ago
It will output 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
BE
Beth
2 years ago
I'm not sure, but I think the answer might be C) program outputs 1 1 1 1 1 1 1 1 1 1 1 2 3 4 5 because of the way the vectors are being manipulated.
AN
Andrew
2 years ago
I agree with Goldie, the code looks like it will not compile correctly.
GO
Goldie
2 years ago
I think the answer is B) compilation error because there seems to be an issue with the code.