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C++ Institute CPP Exam - Topic 4 Question 88 Discussion

Posted by Claribel on Jul 04, 2024 at 06:00 PM

What happens when you attempt to compile and run the following code?

#include

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

};

bool Compare(char a, char b) { return tolower(a) < tolower(b);}

int main() {

char s[]={"qwerty"};

char t1[]={"ert"};

char t2[]={"ERT"};

sort(s, s+6);

cout<

return 0;

}

Program outputs:

Suggested Answer: E

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34 comments · newest first
VA
Vallie 11 months ago
Compare function is case insensitive, so it matters!
TI
Tien 11 months ago
Wait, are you sure about that? Sounds off.
GA
Galen 11 months ago
Definitely 0 1, t2 should match.
DE
Deane 11 months ago
I think the output is 1 1!
YU
Yuonne 11 months ago
The sort function will rearrange the characters in s.
RE
Reuben 12 months ago
I feel like `includes` should return 1 for both `t1` and `t2` since the comparison is case insensitive, but I could be mixing it up with another function.
LU
Lucy 12 months ago
If I remember correctly, after sorting `s`, it should contain the characters in alphabetical order. So, I guess `t1` might be included, but I'm not sure about `t2`.
GL
Glenna 12 months ago
I remember practicing with `includes` before, and I think it checks if all elements of the second range are in the first, but I can't recall if case sensitivity matters.
TA
Tammi 1 year ago
I think the `sort` function will rearrange the characters in `s`, but I'm not sure how `includes` works with the custom comparator.
SH
Sherita 1 year ago
Alright, I've got a good understanding of the code now. I'll work through the logic step-by-step and make sure I can explain what's happening in the output.
CH
Chan 1 year ago
This seems straightforward enough. The `includes` function checks if one range is a subset of another, and the `Compare` function is used to do a case-insensitive comparison. I think I can handle this.
KA
Kaitlyn 1 year ago
I'm a bit confused by the `Compare` function and how it's being used in the `includes` calls. I'll need to review how `tolower` and custom comparison functions work in C++.
DE
Denise 1 year ago
Okay, let's see. The code is sorting the `s` array and then checking if the `t1` and `t2` arrays are subsets of the sorted `s` array using the `includes` function. I think I have a strategy for this.
RE
Ressie 1 year ago
Hmm, this looks like a tricky one. I'll need to carefully read through the code and understand what the `includes` function is doing.
RO
Rocco 1 year ago
Hmm, I'm a bit unsure about this one. The objectives all seem related to privacy and data handling, so I'll have to think carefully to determine which one is not an actual objective.
MA
Marlon 1 year ago
Setting seeAllData to 'true' in the test class? That doesn't sound right to me. I'd be worried that could introduce other issues or mask the real problem.
EV
Evangelina 1 year ago
Wait, wait, wait... the 'includes' function is case-sensitive? I thought it was case-insensitive! I guess I need to re-read the C++ documentation more carefully. *facepalm*
MA
Magnolia 1 year ago
The output will be 1 0, because the 'includes' function is case-sensitive, and 't1' (ert) is present in the sorted string 's' (eqrty), but 't2' (ERT) is not, since the comparison is case-sensitive.
RE
Rebecka 1 year ago
↳ replying to Magnolia
D) 1 1
MA
Marge 1 year ago
↳ replying to Magnolia
C) 1 0
TH
Thaddeus 1 year ago
↳ replying to Magnolia
B) 0 1
AL
Altha 1 year ago
↳ replying to Magnolia
A) 0 0
LI
Lizbeth 1 year ago
Hmm, this looks like a tricky one. I'll have to double-check the 'includes' function and the 'Compare' function to be sure, but my guess is that the output will be 0 1.
GE
Gerald 1 year ago
I think the output will be 1 1, because the 'includes' function checks if all the elements in the second range are present in the first range, and both 't1' (ert) and 't2' (ERT) are present in the sorted string 's' (eqrty).
GO
Goldie 1 year ago
↳ replying to Gerald
Oh, I see. Thanks for the explanation.
GO
Goldie 1 year ago
↳ replying to Gerald
No, the output will be 1 0 because 't1' (ert) is present in the sorted string 's' (eqrty) but 't2' (ERT) is not.
GO
Goldie 1 year ago
↳ replying to Gerald
C) 1 0
JA
Jade 1 year ago
The output of the program will be 0 1, as the 'includes' function checks if all the elements in the second range are present in the first range, and the characters in 't2' (ERT) are all present in the sorted string 's' (eqrty), but the characters in 't1' (ert) are not all present in 's'.
MA
Martina 1 year ago
↳ replying to Jade
Characters in 't2' (ERT) are all present in the sorted string 's' (eqrty), but characters in 't1' (ert) are not all present in 's'.
MA
Martina 1 year ago
↳ replying to Jade
The 'includes' function checks if all elements in the second range are present in the first range.
MA
Martina 1 year ago
↳ replying to Jade
B) 0 1
RI
Rickie 2 years ago
Why do you think it's C) 1 0?
SK
Skye 2 years ago
I disagree, I believe the correct answer is C) 1 0.
RI
Rickie 2 years ago
I think the answer is B) 0 1.
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