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C++ Institute CPP Exam - Topic 4 Question 70 Discussion

Posted by Daniela on Aug 05, 2023 at 08:53 AM

What happens when you attempt to compile and run the following code?

#include

#include

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) { out<

int main() {

int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};

deque d1(t, t+10);

deque::iterator it = lower_bound(d1.begin(), d1.end(), 4);

for_each(it, d1.end(), Out(cout));cout<

return 0;

}

Program outputs:

Suggested Answer: E

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32 comments · newest first
CA
Casie 11 months ago
I thought it would print all the numbers in order, but I guess not!
VA
Vanesa 11 months ago
It's definitely not a compilation error.
CO
Corinne 11 months ago
Wait, are you sure? I thought it would be something else.
DO
Dominque 11 months ago
Totally agree, that's what I got too!
ST
Stefan 12 months ago
The program outputs 4 5 6 7 8 9 10.
MI
Mitsue 12 months ago
I have a feeling there might be a compilation error, but I can't pinpoint why. I should have paid more attention to the iterator usage.
AL
Allene 12 months ago
I practiced a similar question, and I feel like the output could be the elements starting from 4, but I can't recall if it includes 4 itself.
DE
Deane 1 year ago
I remember something about `lower_bound` returning an iterator to the first element not less than the given value, so it might start from 4.
CE
Ceola 1 year ago
I think the code should compile fine since all the includes seem correct, but I'm not sure what the output will be.
CA
Carlee 1 year ago
Based on the information provided, I think option B about emails consuming Super Messages is the most likely explanation. I'll make sure to double-check the details around that in my preparation.
MA
Marshall 1 year ago
Okay, I remember discussing this in class. The capitalization rate should be a blend of the debt and equity components, so I'll select option C.
PE
Pearline 1 year ago
This seems like a straightforward vocabulary question. I'll carefully read through the options and choose the one that best fits the context.
MA
Maryanne 1 year ago
The code looks pretty straightforward, but I can't help but wonder if the programmer had a bad day when they wrote this. Anyway, I'm going with A.
LA
Lashunda 1 year ago
Wait, is the lower_bound function supposed to return the element itself or the first element greater than the value? I'm not sure about the answer.
CA
Carmelina 1 year ago
↳ replying to Lashunda
Exactly, that's why the answer is B.
CA
Carmelina 1 year ago
↳ replying to Lashunda
So the output will start from 4.
CA
Carmelina 1 year ago
↳ replying to Lashunda
It returns the first element greater than or equal to the value.
CA
Carmelina 1 year ago
↳ replying to Lashunda
B) 2 3 4 5 6 7 8 9 10 11
CH
Chuck 1 year ago
Haha, looks like we're sorting a deque in reverse order. The correct answer is C.
RA
Raymon 1 year ago
↳ replying to Chuck
Definitely C, it's sorting in descending order.
RA
Raymon 1 year ago
↳ replying to Chuck
Yeah, it's sorting in reverse. C is the right answer.
RA
Raymon 1 year ago
↳ replying to Chuck
I agree, the correct answer is C.
TY
Ty 1 year ago
I think the code will compile without any errors, so the answer is not E.
AL
Alecia 1 year ago
The output should be 4 5 6 7 8 9 10, so the correct answer is A.
MA
Maddie 1 year ago
↳ replying to Alecia
Great job! You understood the code correctly.
MA
Maddie 1 year ago
↳ replying to Alecia
That's correct! The output is indeed 4 5 6 7 8 9 10.
PA
Patria 1 year ago
↳ replying to Alecia
That's correct! The output should be 4 5 6 7 8 9 10.
MA
Maddie 1 year ago
↳ replying to Alecia
A) 1 2 3 4 5 6 7 8 9 10
PA
Patria 1 year ago
↳ replying to Alecia
A) 1 2 3 4 5 6 7 8 9 10
SH
Shalon 2 years ago
I'm not sure, but I think the answer is A) 1 2 3 4 5 6 7 8 9 10 because lower_bound returns an iterator to the first element that is not less than the value passed, which is 4 in this case.
LE
Lewis 2 years ago
I agree with Viola, the lower_bound function returns an iterator to the first element that is not less than the value passed, so the output should be A) 1 2 3 4 5 6 7 8 9 10.
VI
Viola 2 years ago
I think the answer is A) 1 2 3 4 5 6 7 8 9 10 because lower_bound finds the first element that is not less than 4 in the deque.
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