What happens when you attempt to compile and run the following code? Choose all that apply.#include #include #include #include #include #include using namespace std;templatestruct Out {ostream & out;Out(ostream & o): out(o){}void operator() (const T & val ) {out

Discuss C++ Institute CPP Exam Topic 3 Question 81

What happens when you attempt to compile and run the following code? Choose all that apply.

#include

using namespace std;

templatestruct Out {

ostream & out;

Out(ostream & o): out(o){}

void operator() (const T & val ) {out<

int main () {

int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

fstream f("test.out", ios::trunc|ios::out);

list l(t, t+10);

for_each(l.begin(), l.end(), Out(f));

f.close(); f.open("test.out");

for( ; f.good() ; ) {

int i; f>>i;

cout<

}

f.close();

return 0;

}

Afile test.out will be opened writing

Bfile test.out will be truncated

Cfile test.out will be opened for reading

Dno file will be created nor opened

Eprogram will display sequence 1 2 3 4 5 6 7 8 9 10

Suggested Answer: E

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34 comments · newest first

Shalon 11 months ago

No file will be created? That seems off.

Makeda 11 months ago

Wait, are you sure the file opens for reading after writing?

Torie 11 months ago

I think it will display the sequence correctly.

Boris 11 months ago

Yeah, it gets truncated first!

Niesha 11 months ago

The file test.out will be opened for writing.

Devon 12 months ago

I practiced a similar question, and I think option E might be wrong because the output format could be different with hex values.

Alberta 12 months ago

I feel like option C could be true too, since the file is opened again later for reading.

Long 12 months ago

I'm not sure about option B, but I remember something about truncating files when opening them in that mode.

Allene 1 year ago

I think option A is correct because the file is opened for writing initially.

Lynna 1 year ago

Hmm, I'm not sure about the file handling here. I'll need to double-check the file modes and make sure I understand how the reading and writing are happening.

Leah 1 year ago

I feel pretty confident about this one. The code is opening the file in truncate mode, writing the values to it, and then reading them back out. The output should be the sequence of numbers.

Devora 1 year ago

Okay, let me think this through step-by-step. The code is opening a file, writing some data to it, and then reading from the file. I'll need to consider the file modes and how that affects the behavior.

Elke 1 year ago

This looks like a tricky question. I'll need to carefully read through the code and understand what's happening with the file operations and the output.

Georgiann 1 year ago

I'm a bit confused by the use of the `for_each` algorithm and the `Out` struct. I'll need to make sure I understand how that's working and how it relates to the file output.

Flo 1 year ago

I'm a little confused by the wording of this question. It's talking about modifying the high-density RF protocol, but I'm not sure how the different settings would impact that. I'll have to review my notes on high-density wireless design to figure this out.

Herman 1 year ago

Microservices architecture has a lot of benefits, but I want to make sure I understand them all before answering. I'll review my notes quickly.

Ronny 1 year ago

No problem, I've got this. I know these manufacturing types well, so I'll breeze through this question.

Mozell 1 year ago

This code is making my head spin! I wonder if the author had a thesaurus nearby when they wrote it. 'Truncate' and 'hexadecimal' in the same question? Yikes!

Ruth 1 year ago

↳ replying to Mozell

The code seems to involve file handling and output formatting.

Iesha 1 year ago

Hmm, I'm not sure about option C. Doesn't the code open the file for writing, not reading? I think I'll go with A, B, and E.

Matthew 1 year ago

↳ replying to Iesha

Let's go with options A, B, and E then.

Brynn 1 year ago

↳ replying to Iesha

Yeah, I agree. So option C is not correct.

Gary 1 year ago

↳ replying to Iesha

I think you're right, the code opens the file for writing, not reading.

Margurite 1 year ago

Wow, this code is really complex! I'm not sure I would have thought to use `for_each` and a custom functor to write the values to a file. That's some pretty advanced C++ right there.

Justa 1 year ago

↳ replying to Margurite

User3: I would have never thought to do it that way, it's impressive.

Levi 1 year ago

↳ replying to Margurite

User2: I agree, using for_each with a custom functor is pretty advanced.

Lelia 1 year ago

↳ replying to Margurite

User1: Yeah, this code is definitely not for beginners.

Malika 1 year ago

I think the code looks good, but I'm a bit concerned about the use of `for_each` with a lambda function. Isn't that a bit overkill for this task? I would have just used a simple `for` loop.

Nguyet 1 year ago

↳ replying to Malika

What happens when you attempt to compile and run the following code? Choose all that apply.

Jacinta 1 year ago

↳ replying to Malika

What happens when you attempt to compile and run the following code? Choose all that apply.

Iluminada 1 year ago

The correct answers are A, B, and E. The code creates a file named 'test.out', writes the values of the array to the file in hexadecimal format, and then reads the contents of the file and displays them on the console.

Tamesha 2 years ago

I'm not sure, but I think the program will display the sequence 1 2 3 4 5 6 7 8 9 10 (E) in the end.

Michel 2 years ago

I believe the file test.out will be truncated (B) when the code is compiled and run.

Grover 2 years ago

I think the file test.out will be opened for writing (A).

C++ Institute CPP Exam - Topic 3 Question 81 Discussion