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What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 1, 5, 2, 5, 2, 4, 4, 3, 3, 1 };
vector
set
replace(v1.begin(), v1.end(), 1, 10);
replace(s1.begin(), s1.end(), 1, 10);
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
Suggested Answer: C
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8 comments · newest first
LA
Latanya
11 months ago
Definitely B, right?
FR
France
12 months ago
I’m pretty sure it’ll print 10 for the vector but not for the set.
GA
Gabriele
12 months ago
Wait, does the set really ignore duplicates?
RY
Ryan
12 months ago
I think the output should be D.
SU
Sue
1 year ago
The set won't change, so it still has 1.
WI
Wilda
1 year ago
I think I know this one - a service template would be used to apply the same configuration to multiple CPEs, like option B. That seems like a common use case.
MI
Ming
1 year ago
I'm pretty confident I know the answer to this one. HDFEC is simpler and faster than SDEFC, so option A is the false statement. I'll mark that one.
SA
Sarah
1 year ago
I'm pretty sure the no-arbitrage condition plays a key role in these problems. I just wish I could recall the exact formula we used for pricing these Treasury bond forwards.