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What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
using namespace std;
class A
{
int a;
public:
A(int a) {this?>a = a; c++;}
A(const A & a) {this?>a = a.a; c++;}
~A() { c??;}
static int c;
};
int A::c(0);
int main ()
{
A* t[] = {new A(1), new A(2), new A(3),new A(4), new A(5)};
vector
deque
d1.clear();
v1.clear();
cout< return 0; }
Suggested Answer: B, D
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8 comments · newest first
LI
Lindy
11 months ago
Yeah, the destructor should be called for each object.
CH
Charolette
12 months ago
I thought it would show 0 since they get cleared.
LA
Laurel
12 months ago
Wait, does the destructor get called for all of them?
LI
Lili
1 year ago
Totally agree, the constructor runs 5 times.
AL
Alpha
1 year ago
There are 5 A objects created.
DE
Denae
1 year ago
Alright, this seems straightforward. The export policy shows that R1 is advertising an aggregate route, so the AS path should be 65540.
JA
Jaime
1 year ago
I want to say it's the security group tag number, but was it specific to ports or users? That's what confuses me.
HY
Hyman
1 year ago
Hmm, I'm a bit unsure about this one. The options seem similar, but I think the key is understanding the difference between information and knowledge. Let me think this through carefully.