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What happens when you attempt to compile and run the following code?
#include
using namespace std;
class A {
public:
int x;
A() { x=0;}
};
class B : protected A {
public:
int y;
using A::x;
B(int y) {this?>y = y;}
void Print() { cout << x << y; }
};
int main () {
B b(5);
b.Print();
return 0;
}
Suggested Answer: A
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12 comments · newest first
MA
Maryann
1 month ago
I'm leaning towards 15. The constructor might be messing things up.
AN
Angella
1 month ago
I feel like it should print 0. The y isn't set correctly.
DI
Dick
1 month ago
I think it prints 05. The x is initialized to 0.
DI
Diane
2 months ago
Definitely prints 05, that's how inheritance works!
VE
Venita
2 months ago
Wait, how does it even access x like that?
AL
Alishia
2 months ago
No way, it should be 15!
SH
Shawn
2 months ago
I think it should print 0, right?
FR
Francesco
2 months ago
It prints: 05
GL
Glenn
2 months ago
I feel like it should print 05 since x is initialized to 0 and y is set to 5 in the constructor.
SK
Skye
3 months ago
I practiced a similar question where the output was affected by member access. This one seems tricky!
AL
Alease
3 months ago
I'm not entirely sure, but I remember something about protected members. Maybe it won't print y at all?
YO
Yoko
3 months ago
I think the constructor for B isn't setting x correctly, so it might just print 0.