Confluent CCDAK Exam - Topic 3 Question 78 Discussion

Actual exam question for Confluent's CCDAK exam

Question #: 78
Topic #: 3

Suppose you have 6 brokers and you decide to create a topic with 10 partitions and a replication factor of 3. The brokers 0 and 1 are on rack A, the brokers 2 and 3 are on rack B, and the brokers 4 and 5 are on rack C. If the leader for partition 0 is on broker 4, and the first replica is on broker 2, which broker can host the last replica? (select two)

Show Suggested Answer

Suggested Answer: B, E

When you create a new topic, partitions replicas are spreads across racks to maintain availability. Hence, the Rack A, which currently does not hold the topic partition, will be selected for the last replica

by Teddy at May 02, 2025, 10:44 PM

Limited Time Offer

25%

Off

Get Premium CCDAK Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Barney

2 months ago

Broker 0 could also work, right?

upvoted 0 times

...

Jade

2 months ago

I think it can only be broker 5.

upvoted 0 times

...

Jesusa

2 months ago

The last replica has to be on a different rack.

upvoted 0 times

...

Otis

3 months ago

Wait, are you sure about that?

upvoted 0 times

...

Filiberto

3 months ago

Totally agree, it has to be 5!

upvoted 0 times

...

Simona

3 months ago

I feel like broker 0 might be a good choice, but I’m not completely sure about broker 3.

upvoted 0 times

...

Ilona

3 months ago

I practiced a similar question, and I think the last replica has to be on a different rack from the leader and the first replica.

upvoted 0 times

...

Lisandra

4 months ago

I remember something about rack awareness, but I'm not sure if that means we can choose broker 1 or 5.

upvoted 0 times

...

Alline

4 months ago

I think the last replica can't be on the same rack as the leader, so it can't be broker 4.

upvoted 0 times

...

Jaime

4 months ago

This is a tricky one, but I'm confident I can work through it. I just need to carefully consider the rack assignments and the existing replica locations.

upvoted 0 times

...

Benedict

4 months ago

Alright, I think I've got it. The last replica needs to be on a broker that's not on rack A or B. So the answer must be brokers 0, 3, or 5.

upvoted 0 times

...

Denae

4 months ago

I'm a bit confused by the rack assignments. I'll need to draw this out to visualize the broker locations and make sure I understand where the replicas can be placed.

upvoted 0 times

...

Precious

5 months ago

Okay, let's see. The leader for partition 0 is on broker 4, and the first replica is on broker 2. So the last replica needs to be on a broker that's not on the same rack as 4 or 2. I think I've got this!

upvoted 0 times

...

Miles

5 months ago

Hmm, this looks tricky. I'll need to carefully think through the broker and partition assignments to figure out the valid options.

upvoted 0 times

...

Monroe

8 months ago

Hmm, this question is making my brain hurt. Maybe I should have had one more cup of coffee before the exam. But hey, at least it's not as bad as the time I accidentally put my answer sheet through the shredder. Good times, good times...

upvoted 0 times

Genevieve

7 months ago

B) 1

upvoted 0 times

...

Tricia

8 months ago

A) 6

upvoted 0 times

...

Carmen

8 months ago

Oh, this is a good one! I bet the answer is going to be something super obvious that I totally overlooked. Let me reread the question and see if I can figure this out... Aha! Got it. C) 2 and F) 3 are the correct answers. Nailed it!

upvoted 0 times

...

Clorinda

8 months ago

This is a classic Kafka partition placement question. Let's think through the constraints. We can't have multiple replicas on the same rack, and the leader has to be on a different broker than the first replica. That leaves brokers 3, 5, and 0 as the viable options for the last replica. Time to mark my answer!

upvoted 0 times

...

Florencia

8 months ago

Alright, I think I've got it. Brokers 0 and 1 are on rack A, so they're not eligible. Brokers 2 and 3 are on rack B, and we already have a replica on broker 2. That leaves brokers 4, 5, and 3 as potential options for the last replica. I'll go with C) 2 and F) 3.

upvoted 0 times

...

Alex

8 months ago

Okay, let's think this through. The topic has 10 partitions, and the replication factor is 3. So, we need to find two brokers that can host the last replica for partition 0, given that the leader is on broker 4 and the first replica is on broker 2. Hmm, this is a tricky one.

upvoted 0 times