CompTIA Exam PT0-002 Topic 1 Question 57 Discussion

Actual exam question for CompTIA's PT0-002 exam

Question #: 57
Topic #: 1

A penetration tester conducted a discovery scan that generated the following:

Which of the following commands generated the results above and will transform them into a list of active hosts for further analysis?

Anmap --oG list.txt 192.168.0.1-254 , sort

Bnmap --sn 192.168.0.1-254 , grep ''Nmap scan'' | awk '{print S5}'

Cnmap ---open 192.168.0.1-254, uniq

Dnmap --o 192.168.0.1-254, cut --f 2

Show Suggested Answer

Suggested Answer: D

In this scenario, the penetration tester performed a 'Tailgating' attack (D), where the tester follows closely behind a legitimate employee to gain unauthorized access to a secure area without being noticed. This social engineering technique relies on exploiting human tendencies to be polite or avoid confrontation, rather than using technical hacking methods. The tester engaged the employee in casual conversation to appear less suspicious and took advantage of the situation when the employee, perhaps distracted or feeling socially obliged, held the door open for them.

by Altha at May 20, 2024, 01:47 AM

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Chantay

2 months ago

I wonder if the person who wrote this question had a little too much coffee before their shift. Some of these options are just plain silly. But hey, at least it keeps us on our toes, right?

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Keith

2 months ago

Option D is definitely a red herring - 'nmap --o 192.168.0.1-254, cut --f 2'? What kind of nonsense is that? B is the only logical choice here.

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Jess

2 months ago

Haha, I bet the test-makers are trying to trick us with those other options. Who would use 'sort' or 'uniq' on Nmap output? Option B is clearly the winner here.

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Cherri

1 months ago

Definitely, option B is the way to go for transforming the results into a list of active hosts.

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Dominic

1 months ago

Yeah, using 'sort' or 'uniq' on Nmap output doesn't make sense.

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Marion

1 months ago

I agree, option B is the most logical choice.

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Yvette

3 months ago

Hmm, the question says the results will be transformed into a list of active hosts, so I'd go with option B as well. Using grep and awk to extract the IP addresses seems like the way to go.

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Jame

2 months ago

I would also choose option B. It looks like the best command to extract the IP addresses for further analysis.

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Alpha

2 months ago

Yeah, I agree. Option B seems like the most efficient way to transform the results into a list of active hosts.

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Jacob

2 months ago

I think option B is the correct one too. Using grep and awk can help extract the IP addresses easily.

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Walker

3 months ago

Okay, let's see... the output looks like a typical Nmap scan result. I think option B is the correct answer here - 'nmap --sn 192.168.0.1-254, grep ''Nmap scan'' | awk '{print $5},'' will give us a list of active hosts.

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Letha

1 months ago

I've used option B before, and it worked perfectly for extracting active hosts. It's definitely the correct command for this scenario.

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Jutta

1 months ago

I'm not sure about option C or D, they don't seem to be the right commands to extract active hosts from the Nmap scan.

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Marjory

2 months ago

That makes sense. Option B is the most efficient way to extract a list of active hosts from the Nmap scan results.

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Jade

2 months ago

I think you're right. Option B uses the --sn flag to perform a ping scan and then filters the output to show only active hosts.

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Audra

2 months ago

I think option A could also work, using the --oG flag to output in a grepable format and then sorting the results.

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Benedict

2 months ago

I agree, option B seems like the right choice. It filters out the active hosts based on the Nmap scan results.

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Sue

2 months ago

I agree, option B seems like the right choice. It filters out the active hosts based on the Nmap scan results.

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Pedro

3 months ago

Hmm, that makes sense. I see your point now.

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Mozell

3 months ago

I disagree, I believe the answer is B) nmap --sn 192.168.0.1-254 , grep ''Nmap scan'' | awk '{print S5}' because it filters out only the active hosts.

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Pedro

3 months ago

I think the correct command is A) nmap --oG list.txt 192.168.0.1-254 , sort.

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