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A developer needs to build a new Docker image and has created a tag by using the command:
$ docker tag 32df423320458 local/app.1.2
Which command must be executed next to build the Docker image using the tag?
A)
B)
C)
D)
Suggested Answer: C
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24 comments · newest first
CA
Carlee
2 days ago
D seems off. I don't recall that command.
PE
Pearly
7 days ago
I'm leaning towards C. It matches my notes.
SH
Sherron
12 days ago
I feel like it could be B. Looks familiar.
VA
Vanesa
17 days ago
I think it's A. Seems straightforward.
BR
Brande
22 days ago
I agree with B. It’s straightforward.
GL
Glory
27 days ago
D seems wrong. B is the best choice.
AM
Amina
1 month ago
I lean towards C. But I’m not confident.
JO
Joaquin
1 month ago
Definitely B. It matches the tagging process.
AU
Audria
1 month ago
I feel unsure. Maybe A?
KA
Katlyn
2 months ago
I think it's B. It looks like the right command.
LI
Lina
2 months ago
Yup, A is the correct choice!
TO
Tora
2 months ago
Wait, is that really the right command?
AR
Art
2 months ago
I thought it was option C at first.
RE
Rebbecca
2 months ago
Definitely going with option A!
BO
Bo
2 months ago
You need to run `docker build` next!
AL
Albert
3 months ago
Wait, can you really build an image just like that?
HE
Helaine
3 months ago
Nah, I think option B is the right one.
RO
Roxane
3 months ago
I thought it was option C at first.
RO
Rolande
3 months ago
Definitely option A!
GL
Gladys
3 months ago
You need to run `docker build` next!
FR
Francine
3 months ago
I vaguely remember that after tagging, we need to build the image, but I can't remember if there's a specific option we need to include.
LA
Latanya
4 months ago
I feel like I might confuse the build command with the run command. Was it `docker build -t` or just `docker build`?
ME
Melvin
4 months ago
I think the command should be `docker build`, but I'm not sure about the syntax. We had a similar question in our last mock exam.
FR
Francine
5 months ago
I remember we practiced the command to build an image, but I can't recall if it was `docker build` or something else.