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CertNexus ITS-110 Exam - Topic 1 Question 59 Discussion

Actual exam question for CertNexus's ITS-110 exam
Question #: 59
Topic #: 1
[All ITS-110 Questions]

An IoT security architect needs to minimize the security risk of a radio frequency (RF) mesh application. Which of the following might the architect consider as part of the design?

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Suggested Answer: B

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Derick
3 months ago
Wait, are we really trusting all gateways? That seems sketchy!
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Jacki
3 months ago
C sounds risky. Keeping all nodes could compromise security.
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Johnetta
3 months ago
D? No way! Implicit trust is a huge red flag.
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Rossana
3 months ago
A is a bad idea. Easy pairing can lead to vulnerabilities.
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Susana
3 months ago
Definitely B! Encrypting data is crucial for security.
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Felicidad
4 months ago
Preventing node rejection sounds like it could lead to issues, but I can't recall the exact implications. Option C might not be the best approach either.
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Elenore
4 months ago
I think we had a practice question about implicit trust before. It seems risky to trust all gateways without verification, so option D feels wrong to me.
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Kent
4 months ago
I'm not entirely sure, but I feel like making pairing easy could lead to vulnerabilities. Maybe option A isn't the best choice?
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Corinne
4 months ago
I remember we discussed the importance of encryption in our last study session. I think option B makes the most sense for securing data transmission.
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Nieves
4 months ago
I'm leaning towards option B as well. Encrypting the data at the physical and logical layers is a fundamental security control that the architect should consider. The other options don't really address the core security needs of an RF mesh application.
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Rashad
5 months ago
Option A seems like a bad idea - making pairing too easy could actually increase security risks. And option D is just plain wrong, you can't just trust all gateways implicitly. I think B is the way to go, encryption is key for securing data transmission in an RF mesh.
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Jean
5 months ago
Hmm, I'm a bit unsure about this one. The options seem to be focused on different aspects of security, but I'm not sure which one would be the best approach for an IoT security architect. I might need to think through the tradeoffs a bit more.
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Cathrine
5 months ago
This seems like a pretty straightforward security question. I'd go with option B - encrypting the data transmission between nodes is a solid way to minimize security risks in an RF mesh application.
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Jonell
6 months ago
Option C, really? Preventing nodes from being rejected? That's like saying we should keep all the stray cats in the neighborhood, just to keep the network 'valuable'. Nope, not happening.
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Lynsey
6 months ago
B) Encrypt data transmission between nodes at the physical/logical layers.
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Terry
7 months ago
Option D is just asking for trouble. Trusting all gateways? That's like giving your house keys to every random person you meet on the street. Not a chance!
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Stephaine
7 months ago
I see your point, Aretha, but I still think encryption is the best way to minimize security risks.
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William
7 months ago
Haha, Option A? Really? Making pairing easy for troubleshooting? That's like leaving your front door unlocked for the convenience of your delivery guy. Hard pass on that one.
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Kris
5 months ago
C) Prevent nodes from being rejected to keep the value of the network as high as possible.
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Kanisha
6 months ago
B) Encrypt data transmission between nodes at the physical/logical layers.
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Aretha
7 months ago
But what about option A? Making pairing easy could also help with troubleshooting.
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Susana
7 months ago
I agree with Lilli, encrypting data transmission is crucial for security.
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Louis
7 months ago
Option B seems like the way to go. Encrypting the data transmission is crucial for IoT security. Gotta keep those packets safe, you know?
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Teddy
5 months ago
User 2: Definitely, encryption is key to keeping the data secure in RF mesh applications.
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Margery
6 months ago
User 1: Option B seems like the way to go. Encrypting the data transmission is crucial for IoT security.
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Lilli
8 months ago
I think the architect should choose option B.
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