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C++ Institute CPA-21-02 Exam - Topic 8 Question 29 Discussion

What happens when you attempt to compile and run the following code?#include using namespace std;int fun(int x) {return 2*x;}int main(){int i;i = fun(1) || fun(2);cout
B) It prints: 1
A) It prints: 0
C) It prints: -1
D) Compilation error

C++ Institute CPA-21-02 Exam - Topic 8 Question 29 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam
Question #: 29
Topic #: 8
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int fun(int x) {

return 2*x;

}

int main(){

int i;

i = fun(1) || fun(2);

cout << i;

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: B

by Avery at Sep 17, 2024, 06:35 PM

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Miles
10 months ago
Definitely not a compilation error, that's for sure.
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Kimi
10 months ago
The logical OR operator returns the first true value, so yeah, 1!
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Alida
11 months ago
Wait, how does it print 1? I'm confused.
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Tijuana
11 months ago
I thought it would be 0, but I guess I was wrong!
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Tyra
11 months ago
It prints: 1
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Paris
11 months ago
I practiced a similar question, and I think the result of `i` will be 1 because of the short-circuit evaluation in the `||` operator.
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Sheron
12 months ago
If I recall correctly, `fun(1)` returns 2 and `fun(2)` returns 4, so the expression should evaluate to true, which is 1.
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Jovita
12 months ago
I'm a bit unsure, but I remember something about logical operators. I think `||` evaluates to true if either side is non-zero.
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Tyisha
12 months ago
I think the `fun` function returns an integer, so there shouldn't be a compilation error.
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Dyan
12 months ago
Okay, let me think this through. The || operator will return the first non-zero operand, or 0 if both operands are 0. So the key will be understanding the return values of the two function calls.
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Lenna
12 months ago
Ah, I think I've got this! The || operator will short-circuit, so the first function call that returns a non-zero value will determine the final result. I'll need to consider the return values of the two function calls.
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Maxima
12 months ago
Hmm, I'm a bit unsure about this one. The || operator can be confusing, and I'm not sure how it interacts with the function calls. I'll need to work through it step-by-step.
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Raul
1 year ago
This looks like a tricky logical operation with the || operator. I'll need to carefully think through the order of evaluation and the return values of the two function calls.
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Vilma
1 year ago
This one seems pretty straightforward. I'm pretty confident I can figure out the right CSS code to center the image horizontally.
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Leontine
2 years ago
I'm not sure, but I think it might be a compilation error because you can't use logical OR with integers.
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Noe
2 years ago
Haha, the correct answer is obviously C. Because, you know, -1 is just a classic programmer's choice for a return value. Who needs 0 or 1 when you have -1, am I right?
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Rodrigo
2 years ago
Got it, thanks for the explanation. Looks like I need to review my logical operators.
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Carmen
2 years ago
I see, but in this case, the return value of fun(1) is 2 and the return value of fun(2) is also 2. So, the logical OR operator won't work as expected.
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Miesha
2 years ago
Oh really? I thought it prints: 1 because the logical OR operator returns true if either operand is true.
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Helaine
2 years ago
No, the correct answer is actually D. There will be a compilation error because you can't use the logical OR operator with integers.
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Lennie
2 years ago
I disagree, I believe it prints 1 because the logical OR operator only evaluates the second operand if the first one is false.
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Yvonne
2 years ago
I think the answer is D. There's a compilation error because the return type of fun(x) is int, but the || operator expects a boolean expression.
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Carylon
2 years ago
The answer is B. The || operator short-circuits, so it will return the first non-zero value it encounters, which is fun(1) = 2.
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Mariann
2 years ago
D) Compilation error
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Carisa
2 years ago
fun(1) returns 2.
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Aron
2 years ago
C) It prints: -1
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Carisa
2 years ago
The || operator short-circuits.
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Carisa
2 years ago
It prints: 1
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Erick
2 years ago
B) It prints: 1
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Beckie
2 years ago
A) It prints: 0
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Viola
2 years ago
I think it prints 1 because the logical OR operator returns true if either operand is true.
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