C++ Institute Exam CPA-21-02 Topic 8 Question 22 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 22
Topic #: 8

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int fun(int x) {

return x<<2;

}

int main(){

int i;

i = fun(1) / 2;

cout << i;

return 0;

}

AIt prints: 0

BIt prints: 1

CIt prints: 2

DIt prints: 4

Show Suggested Answer

Suggested Answer: B

by Graham at Aug 04, 2024, 10:58 AM

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Genevive

3 months ago

Haha, this is a classic bit-shift question! The answer is definitely B) It prints: 1. I remember learning about this in my coding class, where the instructor said, 'Bit-shifting is like magic, but it's also like a secret handshake for programmers.'

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Jeniffer

2 months ago

Oh, I see! So the result is 4, but then divided by 2 to get 2, which is printed out.

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Dorsey

3 months ago

Actually, it prints: 1 because the function fun(1) shifts the binary representation of 1 two positions to the left.

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Shonda

3 months ago

I think the answer is D) It prints: 4.

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Lelia

4 months ago

Hmm, this is a tricky one. I'm going to go with D) It prints: 4. The bit-shift operation must be doing something weird, so let's just go with the largest number in the options.

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Audra

2 months ago

User3: Yeah, let's go with D) It prints: 4

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Mariann

2 months ago

User2: I agree, the bit-shift operation is probably causing that

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Carmen

2 months ago

User1: I think it prints: 4

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Chaya

4 months ago

I think the answer is C) It prints: 2. The bit-shift operation `x<<2` effectively multiplies `x` by 4, so `fun(1)` returns 4, and when divided by 2, the result is 2.

upvoted 0 times