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C++ Institute CPA-21-02 Exam - Topic 7 Question 27 Discussion

What happens when you attempt to compile and run the following code?#include using namespace std;int main(){int i = 4;while(i >= 0) {cout
A) It prints:''43210''
B) It prints:''3210''
C) It prints: ''3210?1''
D) None of these

C++ Institute CPA-21-02 Exam - Topic 7 Question 27 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam
Question #: 27
Topic #: 7
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int main()

{

int i = 4;

while(i >= 0) {

cout<

i??;

}

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: A

by Elina at Sep 18, 2024, 05:57 AM

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Marcos
8 months ago
I agree, it's probably D, none of these!
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Francoise
9 months ago
I think it just won't compile at all.
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Carry
9 months ago
Wait, is "i??;" even valid?
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Roselle
9 months ago
Definitely not A, it won't print that.
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Catrice
9 months ago
Looks like a syntax error with "i??;"
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Nickolas
10 months ago
I feel like it might print "3210" if it somehow skips the error, but that doesn't seem right. I guess I need to think more about the loop structure.
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Giovanna
10 months ago
If I recall correctly, the code won't compile because of the "i??;" part. It seems like a syntax error to me.
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Jamey
10 months ago
I remember practicing a similar question where the loop decremented a variable, but this one looks different with that "??".
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Emily
10 months ago
I think the loop should print the numbers from 4 down to 0, but I'm not sure how the "i??;" affects it.
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Goldie
10 months ago
I'm pretty confident I know the answer here. The loop will print the values of i as it decrements, so the output should be "4321".
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Louis
10 months ago
Wait, what's that extra character at the end? I'm not sure about that part. I'll have to think it through step-by-step.
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Eden
10 months ago
Okay, I think I've got it. The loop will print the value of i, then decrement i until it reaches 0. So the output should be "4321".
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Iesha
10 months ago
This looks like a pretty straightforward loop question. I'll carefully trace the loop to see what the output will be.
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Helene
10 months ago
Hmm, I'm a bit confused about the i-- part. Is that a valid decrement operator? I'll need to double-check the syntax.
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Raina
10 months ago
Hmm, I'm a little unsure about this one. I know reinforcing consequences are supposed to decrease the likelihood of a behavior, but some of these options seem a bit ambiguous. I'll have to really analyze each one closely.
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Makeda
2 years ago
Hmm, I think the answer is B. The post-decrement operator will cause the value of i to be printed first, and then it will be decremented. So the output should be '3210'.
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Iluminada
2 years ago
Haha, that's a classic one! I remember getting tripped up by the post-decrement operator before. This is going to be a good test of our attention to detail.
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Therese
2 years ago
User 3: None of these
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Reta
2 years ago
User 2: I think it prints: '3210'
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Domitila
2 years ago
It prints: '3210?1'
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Magnolia
2 years ago
I'm not sure, but I think it will print '3210'
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Harley
2 years ago
Wait, what's that i-- thing doing? Isn't that supposed to decrement the value of i?
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Donte
2 years ago
Okay, let's think this through. The code is incrementing the value of i by 1 in each iteration, so it should print the numbers in descending order, right?
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Noah
2 years ago
C) It prints: '3210?1'
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Tom
2 years ago
None of these
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Meaghan
2 years ago
B) It prints: '3210'
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Samira
2 years ago
I think it prints: ''3210''
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Horace
2 years ago
A) It prints: '43210'
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Louis
2 years ago
No, it prints: ''3210''
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Pa
2 years ago
It prints: ''3210?1''
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Jovita
2 years ago
I agree with Gerardo, because the loop starts at 4 and goes down to 0
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Gerardo
2 years ago
I think it will print '3210'
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