C++ Institute Exam CPA-21-02 Topic 5 Question 28 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam

Question #: 28
Topic #: 5

[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

class complex{

double re;

double im;

public:

complex() : re(1),im(0.4) {}

bool operator==(complex &t);

};

bool complex::operator == (complex &t){

if((this?>re == t.re) && (this?>im == t.im))

return true;

else

return false;

}

int main(){

complex c1,c2;

if (c1==c2)

cout << "OK";

else {

cout << "ERROR";

}

AIt prints: OK

BIt prints: ERROR

CCompilation error

DRuntime error.

Show Suggested Answer

Suggested Answer: A

by Angelyn at Sep 15, 2024, 08:35 PM

Limited Time Offer

25%

Off

Get Premium CPA-21-02 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

Submit Cancel

Layla

10 months ago

D, runtime error. I bet the compiler will yell at us for trying to compare complex numbers without overloading the == operator properly. Whoever wrote this code needs to go back to Complex Numbers 101!

upvoted 0 times

Zona

10 months ago

Definitely a compilation error. The code needs to be fixed before it can run properly.

upvoted 0 times

...

Glendora

10 months ago

Yeah, I agree. The code is trying to compare complex numbers without the proper operator overloading.

upvoted 0 times

...

Adolph

10 months ago

I think it will print ERROR because the == operator is not properly overloaded for complex numbers.

upvoted 0 times

...

Mitsue

11 months ago

I'm not sure, but I think it will print ERROR because the operator== function is not correctly implemented.

upvoted 0 times

...

Joni

11 months ago

Easy peasy, the answer is A! The code will print 'OK' because the default constructor sets the values for c1 and c2, and the overloaded == operator compares them correctly.

upvoted 0 times

...

Beckie

11 months ago

Hmm, I'm not sure. The code looks a bit complex (no pun intended), but I'll go with C, compilation error. There's something about the overloaded == operator that doesn't look quite right.

upvoted 0 times

Callie

10 months ago

Looks like we all think it's a compilation error. Let's see if that's the case.

upvoted 0 times

...

Wilford

11 months ago

I agree with User1 and User2. The code will not compile due to the missing return type in the overloaded operator.

upvoted 0 times

...

Marylou

11 months ago

User1, you're correct. The code will print 'ERROR' because the overloaded == operator is missing a return type.

upvoted 0 times

...

Bobbye

11 months ago

It prints: ERROR

upvoted 0 times

...

Stevie

11 months ago

I think the answer is B, it prints ERROR. The constructor of the complex class initializes the real part to 1 and the imaginary part to 0.4, so c1 and c2 will not be equal.

upvoted 0 times