Deal of The Day! Hurry Up, Grab the Special Discount - Save 25% - Ends In 00:00:00 Coupon code: SAVE25
Welcome to Pass4Success

- Free Preparation Discussions
Mail Us support@pass4success.com
Location US
Mob_nav_barsMENU

C++ Institute CPA-21-02 Exam - Topic 5 Question 25 Discussion

What happens when you attempt to compile and run the following code?#include using namespace std;int mul (int a, int b=2){int r;r=a*b;return (r);}int main (){cout
A) It prints: 2
B) It prints: 28
C) It prints: 8
D) It prints: 6

C++ Institute CPA-21-02 Exam - Topic 5 Question 25 Discussion

Actual exam question for C++ Institute's CPA-21-02 exam
Question #: 25
Topic #: 5
[All CPA-21-02 Questions]

What happens when you attempt to compile and run the following code?

#include

using namespace std;

int mul (int a, int b=2)

{

int r;

r=a*b;

return (r);

}

int main ()

{

cout << mul(1) << mul(2,4);

return 0;

}

Show Suggested Answer Hide Answer
Suggested Answer: A

by Merissa at Sep 15, 2024, 03:10 PM

Limited Time Offer

25%

Off

Get Premium CPA-21-02 Questions as Interactive Web-Based Practice Test or PDF

Contribute your Thoughts:

0/2000 characters
Submit Cancel
Melinda
10 months ago
The default parameter really changes things!
upvoted 0 times
...
Brandon
10 months ago
I thought it would be 8, not 6.
upvoted 0 times
...
Shalon
10 months ago
Wait, how does it get 6?
upvoted 0 times
...
Jean
11 months ago
Totally agree, that's the right output!
upvoted 0 times
...
Billy
11 months ago
It prints: 6
upvoted 0 times
...
Percy
11 months ago
I feel like the output should be 6 because mul(1) gives 2 and mul(2, 4) gives 8, but I might be mixing things up.
upvoted 0 times
...
Tracey
11 months ago
I practiced a similar question, and I think the total output would be 2 + 8, which makes 10, but that’s not an option here.
upvoted 0 times
...
Nada
11 months ago
I'm not entirely sure, but I think the second call mul(2, 4) would multiply 2 by 4, giving 8.
upvoted 0 times
...
Effie
12 months ago
I remember that default parameters can be tricky. I think mul(1) would use the default value of 2, so that would be 1 * 2.
upvoted 0 times
...
Luz
12 months ago
Wait, I'm not sure about that. Let me double-check the logic here. I don't want to make any assumptions.
upvoted 0 times
...
Tamekia
12 months ago
I'm feeling pretty confident about this one. The output should be 2 and 8, for a total of 10.
upvoted 0 times
...
Marshall
12 months ago
Okay, I think I've got this. The first call to mul() will use the default parameter of 2, and the second call will use the explicit parameter of 4.
upvoted 0 times
...
Tonja
12 months ago
Hmm, I'm a bit confused by the default parameter in the function. I'll need to make sure I understand how that works.
upvoted 0 times
...
Norah
12 months ago
This looks like a tricky one. I'll need to carefully read through the code and think through the function calls.
upvoted 0 times
...
Britt
12 months ago
Hmm, I'm a bit unsure about this one. I know the SLA is important, but I'm not totally clear on what the auditor's main goal should be. I'll need to review the details of the question and think through the different options carefully.
upvoted 0 times
...
Jamal
1 year ago
Hmm, let's see... if the default parameter is 2, does that mean the function is called 'mul'? I bet the real answer is 'divide'! *wink wink*
upvoted 0 times
Elenora
1 year ago
It prints: 2 8
upvoted 0 times
...
Elenora
1 year ago
The default parameter is 2, so it multiplies the values.
upvoted 0 times
...
Elenora
1 year ago
No, the function is called 'mul' not 'divide'.
upvoted 0 times
...
...
Ronna
1 year ago
Aha, I know this one! The default parameter in 'mul' is 2, so 'mul(1)' will give us 2. And 'mul(2,4)' will give us 8. Therefore, the answer is A) It prints: 2. Easy peasy!
upvoted 0 times
Bambi
1 year ago
Yes, the default parameter kicks in for the first call to mul.
upvoted 0 times
...
Glory
1 year ago
I think you're right, it should print 2 and 8.
upvoted 0 times
...
...
Truman
1 year ago
Wait, wait, wait... I think I got this. The default parameter in 'mul' is 2, so 'mul(1)' will give us 2. And 'mul(2,4)' will give us 8. Putting them together, the answer must be B) It prints: 28. Nailed it!
upvoted 0 times
...
Refugia
1 year ago
This is easy! The default parameter in the 'mul' function is 2, so 'mul(1)' will return 2. Then 'mul(2,4)' will return 8. Add them up, and the answer is C) It prints: 8.
upvoted 0 times
Roslyn
1 year ago
When you add them up, it prints 8.
upvoted 0 times
...
Jose
1 year ago
So 'mul(1)' returns 2 and 'mul(2,4)' returns 8.
upvoted 0 times
...
Raul
1 year ago
Yes, that's correct! The default parameter is 2 in the 'mul' function.
upvoted 0 times
...
Jani
1 year ago
I think the answer is C) It prints: 8
upvoted 0 times
...
...
Fatima
1 year ago
Hmm, let's see... if the default value for the second parameter in the 'mul' function is 2, then calling 'mul(1)' should give us 2. And 'mul(2,4)' should give us 8. So the answer must be D) It prints: 6.
upvoted 0 times
...
Fairy
1 year ago
But if you look at the code, when mul(1) is called, it uses the default value of b which is 2, so it should be 1*2=2. And when mul(2,4) is called, it should be 2*4=8. So the answer should be B) It prints: 28.
upvoted 0 times
...
Merri
1 year ago
I disagree, I believe the answer is C) It prints: 8.
upvoted 0 times
...
Fairy
1 year ago
I think the answer is B) It prints: 28.
upvoted 0 times
...

Save Cancel