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BCS CTFL4 Exam - Topic 4 Question 41 Discussion

Actual exam question for BCS's CTFL4 exam

Question #: 41
Topic #: 4

[All CTFL4 Questions]

Consider the following simplified version of a state transition diagram that specifies the behavior of a video poker game:

What Is the minimum number of test cases needed to cover every unique sequence of up to 3 states/2 transitions starting In the "Start" state and ending In the "End" state?

A1

B2

C3

D4

Show Suggested Answer

Suggested Answer: D

The minimum number of test cases needed to cover every unique sequence of up to 3 states/2 transitions starting in the ''Start'' state and ending in the ''End'' state is 4. This is because there are 4 unique sequences of up to 3 states/2 transitions starting in the ''Start'' state and ending in the ''End'' state:

Start -> Bet -> End

Start -> Deal -> End

Start -> 1st Deal -> End

Start -> 2nd Deal -> EndReference: ISTQB Certified Tester Foundation Level (CTFL) v4.0 sources and documents.

by Lavelle at May 16, 2026, 06:03 AM

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Mireya

3 days ago

I think it’s 4 test cases.

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Alexia

8 days ago

Definitely 4, gotta cover all the transitions!

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Joye

13 days ago

I counted 3, but I might be missing something.

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Angelica

18 days ago

Wait, are we sure about that? Seems like it could be less.

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Veta

23 days ago

Totally agree, 4 makes sense for full coverage.

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Ariel

28 days ago

I think it’s 4 test cases.

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Edelmira

1 month ago

I believe the answer is 2, based on the transitions we discussed in class. But I should double-check the diagram to be sure!

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Jerry

1 month ago

I recall that we need to cover all transitions, but I’m a bit confused about how to handle the maximum of 3 states. Could it be 4 test cases?

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Isreal

1 month ago

I think we might need to consider each possible path from "Start" to "End." I feel like it could be 3 test cases, but I’m not entirely confident.

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Clorinda

3 months ago

I remember we practiced a similar question about state transitions, but I’m not sure how to count the unique sequences here.

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