Avixa CTS-I Exam - Topic 2 Question 1 Discussion

Actual exam question for Avixa's CTS-I exam

Question #: 1
Topic #: 2

[All CTS-I Questions]

The total impedance of a circuit wired in series is represented by the formula _____.

AP = I * E

BZT =1 / [(1 / Z1) + (1 / Z2) + (1 / Z3) ... + (1 / ZN)]

CZT = Z1 + Z2 + Z3 ... + ZN

DZT =1 / (Z1 + Z2 + Z3 ... + ZN)

Show Suggested Answer

Suggested Answer: C

by Bernardo at Apr 01, 2026, 04:31 PM

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Nieves

23 days ago

I was torn between C and B, but C is definitely right. Simple addition!

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Yong

28 days ago

Agreed! C makes sense. Impedance just adds up in series.

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Gearldine

1 month ago

I think the answer is C. It's straightforward for series circuits.

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Bernadine

1 month ago

C is definitely correct, no doubt!

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Dottie

1 month ago

I thought it was A) P = I * E at first.

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Wilda

2 months ago

Wait, are we sure about that? Seems too simple.

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Mila

3 months ago

Totally agree, that's the right one!

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Glen

3 months ago

It's C) ZT = Z1 + Z2 + Z3 ... + ZN.

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Thea

4 months ago

I keep mixing up the series and parallel formulas, but I think D is for parallel circuits, so it can't be right for this question.

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Lore

4 months ago

I practiced a similar question, and I believe the correct answer is C, since in series, you add the impedances directly.

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Erinn

4 months ago

I'm not entirely sure, but I remember something about the formula for total impedance being different for series and parallel circuits.

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Celia

5 months ago

I think the total impedance in a series circuit is just the sum of the individual impedances, so it might be C?

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