Avixa CTS-I Exam - Topic 2 Question 1 Discussion

Actual exam question for Avixa's CTS-I exam

Question #: 1
Topic #: 2

[All CTS-I Questions]

The total impedance of a circuit wired in series is represented by the formula _____.

AP = I * E

BZT =1 / [(1 / Z1) + (1 / Z2) + (1 / Z3) ... + (1 / ZN)]

CZT = Z1 + Z2 + Z3 ... + ZN

DZT =1 / (Z1 + Z2 + Z3 ... + ZN)

Show Suggested Answer

Suggested Answer: C

by Bernardo at Apr 01, 2026, 04:31 PM

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6 days ago

Totally agree, that's the right one!

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11 days ago

It's C) ZT = Z1 + Z2 + Z3 ... + ZN.

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1 month ago

I keep mixing up the series and parallel formulas, but I think D is for parallel circuits, so it can't be right for this question.

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1 month ago

I practiced a similar question, and I believe the correct answer is C, since in series, you add the impedances directly.

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1 month ago

I'm not entirely sure, but I remember something about the formula for total impedance being different for series and parallel circuits.

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2 months ago

I think the total impedance in a series circuit is just the sum of the individual impedances, so it might be C?

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