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ASTQB Exam - Topic 9 Question 55 Discussion

You are testing an application for a smart phone. You have determined that you only need to test one device from the target family of devices because the behavior of all devices in that family will be the same for this application.This is an example of what test design technique?
B) Combinatorial
A) Boundary value analysis
C) Decision tables
D) Equivalence Partitioning

ASTQB Exam - Topic 9 Question 55 Discussion

Actual exam question for ASTQB's ASTQB exam
Question #: 55
Topic #: 9
[All ASTQB Questions]

You are testing an application for a smart phone. You have determined that you only need to test one device from the target family of devices because the behavior of all devices in that family will be the same for this application.

This is an example of what test design technique?

Show Suggested Answer Hide Answer
Suggested Answer: B

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Lashawn
8 months ago
Yep, just one device is enough for this case!
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Emelda
8 months ago
Sounds too good to be true, I have my doubts.
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Yun
9 months ago
Wait, are we sure all devices behave the same?
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Jannette
9 months ago
I agree, makes sense to test one device.
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Krissy
9 months ago
That's definitely Equivalence Partitioning!
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Cherri
9 months ago
I feel like equivalence partitioning is the best fit here, since we're assuming similar behavior across devices.
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Sherly
10 months ago
This reminds me of a practice question we did on combinatorial testing, but I don't think that's the right answer for this scenario.
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Crista
10 months ago
I'm not entirely sure, but I remember something about boundary value analysis focusing on the edges of input ranges, which doesn't seem to fit here.
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Gayla
10 months ago
I think this might be related to equivalence partitioning since we're treating all devices in the family as one group.
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Gail
10 months ago
I'm feeling pretty confident about this one. The key is recognizing that we can test a single representative device from the family, which is the essence of equivalence partitioning. I'll mark that as my answer.
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Brock
10 months ago
Okay, let me walk through this step-by-step. We have a set of devices, and we only need to test one of them because the behavior is the same across the family. That sounds like the definition of equivalence partitioning to me.
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Chantay
10 months ago
Hmm, I'm a bit unsure about this one. Is it really equivalence partitioning, or could it be something else like boundary value analysis? I'll need to think it through carefully.
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Bulah
10 months ago
This seems like a straightforward equivalence partitioning question. Since the application behavior is the same across all devices in the target family, we only need to test one representative device.
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Augustine
10 months ago
Ah, I've seen questions like this before. Definitely equivalence partitioning - we're grouping the devices into one partition since they all have the same behavior for this application.
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Gladys
10 months ago
I'd be cautious about asking the stakeholder to descope the compliance - that could create bigger issues down the line.
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Dulce
10 months ago
Hmm, I'm a little unsure about this one. I'm debating between B and C. I know we need to develop estimates, but I'm not sure if that's the very next step after getting the program charter accepted.
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Tayna
10 months ago
Wait, but it's also used for all transactions in the Customer application. That makes me think it could be an Internal Logical File (ILF).
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Madalyn
10 months ago
This seems like a straightforward Agile question. I'll focus on the key elements of a retrospective - what went well, what could have gone better, and what we should try next.
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Torie
10 months ago
I think I've got it. The private key is used to generate the public key, and the public key is used to verify transactions. The private key should never be shared.
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Pansy
1 year ago
Equivalence Partitioning for sure. I just hope the exam doesn't throw any curveballs at us!
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Barrett
1 year ago
I'm going with D) Equivalence Partitioning. Seems like the most straightforward answer to me.
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Sang
1 year ago
I would go with D) Equivalence Partitioning as well. It just makes sense in this scenario.
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Louvenia
1 year ago
I've always found Equivalence Partitioning to be the most efficient method.
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Whitney
1 year ago
I think it's C) Decision tables, but I see your point with D) Equivalence Partitioning.
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Benedict
1 year ago
I agree, D) Equivalence Partitioning is the way to go.
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Carman
1 year ago
Haha, I bet the exam writer is laughing at us for overthinking this. It's obviously Equivalence Partitioning, no doubt about it!
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King
1 year ago
Exactly, the behavior of all devices in the same family will be the same for this application.
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Teresita
1 year ago
Yeah, no need to overthink it. Equivalence Partitioning is the way to go.
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Krystal
1 year ago
I agree, it's definitely Equivalence Partitioning.
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Johana
1 year ago
D) Equivalence Partitioning
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Salley
1 year ago
C) Decision tables
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Elli
1 year ago
B) Combinatorial
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Lashawn
1 year ago
A) Boundary value analysis
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Omer
1 year ago
Wait, isn't this also a form of Boundary Value Analysis? I'm not sure...
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Joni
1 year ago
I think it's a mix of both Boundary Value Analysis and Equivalence Partitioning.
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Rebbeca
1 year ago
Exactly, it falls under the category of Equivalence Partitioning.
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Mabel
1 year ago
Yes, it is also a form of Boundary Value Analysis.
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Elden
1 year ago
D) Equivalence Partitioning
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Gerald
1 year ago
C) Decision tables
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Juan
1 year ago
B) Combinatorial
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Fredric
1 year ago
A) Boundary value analysis
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Nana
1 year ago
Definitely D) Equivalence Partitioning. Testing one device from the target family is a classic example of this technique.
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Derick
1 year ago
Exactly, it's an efficient testing technique for sure.
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Arlyne
1 year ago
That makes sense, it's a smart way to save time and effort.
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Wai
1 year ago
I agree, testing one device covers all devices in the family.
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Cyndy
1 year ago
I think it's D) Equivalence Partitioning.
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Olene
1 year ago
I'm not sure, but I think it could also be C) Decision tables. It's about grouping similar behaviors together.
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Elfrieda
1 year ago
I agree with Antione. Testing one device from the target family makes sense for this technique.
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Antione
1 year ago
I think the answer is D) Equivalence Partitioning.
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