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APICS CPIM-8.0 Exam - Topic 1 Question 9 Discussion

Posted by Evangelina on May 04, 2025 at 04:53 AM

If the total part failure rate of a machine is 0.00055 failures per hour, what would be the mean time between failures (MTBF) in hours?

Suggested Answer: A

The mean time between failures (MTBF) is the inverse of the failure rate. The failure rate is given as 0.00055 failures per hour, so the MTBF is 1/0.00055 = 1,818.2 hours. This means that the average time the machine operates without failing is 1,818.2 hours. Reference: MTBF Formula | How to Calculate Mean Time Between Failure? - EDUCBA, Mean time between failures - Wikipedia


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42 comments · newest first
DU
Dulce 10 months ago
Totally agree with A, solid math there!
YV
Yvette 10 months ago
Definitely A, that makes sense!
JO
Josefa 10 months ago
MTBF is calculated as 1 divided by the failure rate.
TR
Troy 10 months ago
Are we sure about that? Feels off to me.
RU
Rueben 10 months ago
Wait, 1,818.2 hours? That seems way too high.
BE
Bernardine 11 months ago
I think the correct answer is A, but I’m not completely confident. I need to double-check my math!
LI
Lilli 11 months ago
I feel like the answer should be a larger number since it's MTBF, but I’m second-guessing my calculations.
EM
Emogene 11 months ago
I think I practiced a similar question where we had to find MTBF from a failure rate. I’ll try to remember the formula!
AR
Art 11 months ago
I remember MTBF is the inverse of the failure rate, but I’m not sure how to calculate it exactly.
KI
Kimberely 12 months ago
I think I've got it - the MTBF is just the reciprocal of the failure rate, so the answer should be 1/0.00055.
AL
Alyssa 12 months ago
Wait, is the failure rate given per hour or per some other time period? I need to make sure I'm using the right units.
RA
Raymon 12 months ago
Okay, I know the MTBF is the inverse of the failure rate, so this should be a simple division problem.
QU
Quentin 1 year ago
Hmm, I'm a bit unsure about the formula to use here. Let me think this through step-by-step.
AL
Allene 1 year ago
This looks like a straightforward calculation, I should be able to handle this.
AN
Antonio 1 year ago
A) 1,818.2 hours? Wow, that machine must be built like a tank! I wonder if they use it to power a small country or something. Either way, it's got to be the answer.
ER
Ernest 1 year ago
↳ replying to Antonio
D) 0.99945
PA
Patti 1 year ago
↳ replying to Antonio
C) 1.98
LO
Lottie 1 year ago
↳ replying to Antonio
B) 59.99945
PO
Pok 1 year ago
↳ replying to Antonio
A) 1,818.2 hours? Wow, that machine must be built like a tank! I wonder if they use it to power a small country or something. Either way, it's got to be the answer.
LE
Leandro 1 year ago
I agree with Terry, A) 1,818.2 makes sense based on the formula
GO
Goldie 1 year ago
C) 1.98 hours? Really? That can't be right. I'd be surprised if the machine lasted that long without having a meltdown. Time to go back to the drawing board on this one.
TH
Theola 1 year ago
↳ replying to Goldie
B) 59.99945 could also be a possible MTBF value for the machine.
ZA
Zana 1 year ago
↳ replying to Goldie
A) 1,818.2 seems more reasonable for the MTBF of the machine.
SH
Shanda 1 year ago
↳ replying to Goldie
C) I agree, 1.98 hours seems too short for the mean time between failures.
LE
Leatha 1 year ago
↳ replying to Goldie
D) 0.99945
RO
Roosevelt 1 year ago
↳ replying to Goldie
C) 1.98
QU
Quentin 1 year ago
↳ replying to Goldie
B) 59.99945
RA
Raina 1 year ago
↳ replying to Goldie
A) 1,818.2
TE
Terry 1 year ago
But the MTBF is calculated as 1 divided by the failure rate, so it should be A)
BL
Blythe 1 year ago
Hmm, D) 0.99945 is a bit too low, don't you think? I bet the machines would be breaking down every hour if that were the case. Better go with something more reasonable.
FA
Farrah 1 year ago
↳ replying to Blythe
C) 1.98
VI
Vinnie 1 year ago
↳ replying to Blythe
A) 1,818.2
CO
Corinne 1 year ago
I disagree, I believe the answer is B) 59.99945
TE
Terry 1 year ago
I think the answer is A) 1,818.2
AL
Aliza 1 year ago
I'm going with B) 59.99945. It just has a nice, precise feel to it. This exam is all about the details, am I right?
SH
Shannan 1 year ago
↳ replying to Aliza
I agree with you, B) 59.99945 seems like the most precise option.
LY
Lynelle 1 year ago
↳ replying to Aliza
I'm not sure, but I'm leaning towards C) 1.98.
CA
Catarina 1 year ago
↳ replying to Aliza
I think A) 1,818.2 is the correct answer.
KA
Karl 1 year ago
A) 1,818.2 seems like the right answer. I mean, if the failure rate is super low, the mean time between failures has to be pretty high, right?
DO
Donte 1 year ago
↳ replying to Karl
C) Yeah, it makes sense that the mean time between failures would be high with a low failure rate like that.
GR
Grover 1 year ago
↳ replying to Karl
B) I think you're right. A high mean time between failures would make sense with such a low failure rate.
JE
Jerlene 1 year ago
↳ replying to Karl
A) 1,818.2 seems like the right answer. I mean, if the failure rate is super low, the mean time between failures has to be pretty high, right?
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